Question

Please solve my question. [Kindly see the attached image for question].

Answer 1

[see the attachment ]

❁given :- data in table form

❁to find : - median

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N = 90

$\frac{n}{2} = \frac{90}{2} = 45$

the cumulative frequency just greater than n/2 is 45 and corresponding class is 40-50

thus ,

40-50 is the median class .such that l=40,f=25,f=20,h=10

$\therefore \: median = \frac{l + \frac{n}{2} - f }{f} \times h \\ median = \frac{40 + </u><u>9</u><u>0</u><u>/</u><u>2</u><u> - </u><u>2</u><u>0</u><u>}{25} \times 10 \\ median = </u><u>5</u><u>0</u><u>$

☯hence , median = 50

________________________________

Answer 2

n=90

n/2 = 45

L= 40

h = 10

cf= 25

md. = l+ {n/2 - cf × h}

__________

f

therefore, md = 40+[ 150]

____

25

therefore, md =8