Question

please solve my question quick

Answer 1

Given
$x + \frac{1}{x} = 11$

Now , We know that

$({x + \frac{1}{x} })^{2} = {x}^{2} + ({\frac{1}{x} )}^{2} + 2 \frac{x}{x} \\ \\ ( {x + \frac{1}{x} })^{2} = {x}^{2} + ( { \frac{1}{x} })^{2} + 2 \\ \\ ( {x + \frac{1}{x} })^{2} - 2 = {x}^{2} + ( { \frac{1}{x} })^{2} \\ \\ {11}^{2} - 2 = {x}^{2} + ( { \frac{1}{x} })^{2} \\ \\ 121 - 2 = {x}^{2} + ( { \frac{1}{x} })^{2} \\ \\ {x}^{2} + ( { \frac{1}{x} })^{2} = 119$

Answer 2

Given,

X + 1/X = 11

Squaring both sides,we get.

(X + 1/X)^2 = X^2 + 2.X.1/X + (1/X)^2

=> (11)^2 = X^2 + 2 + 1/X^2

=> 121 = X^2 + 2 +1/X^2

=> 121 - 2 = X^2 + 1/X^2

=> 119 = X^2 + 1/X^2

•°• X^2 + 1/X^2 = 119