Question

please solve my question step by step ☺☺☺☺

if any one is give write solution then I will mark as brainlist

Answer 1

Hey !!!

(A + B )'s work in one day = 1/20 ---1)
(B + C ) 's work in one day = 1/30 ----2)
(C + A ) 's work in one day = 1/40------3)

Adding thrice equation

we get ,

(A + B + B + C + C + A ) = 1/20 + 1/30 + 1/40

2( A + B + C ) = 13/120

(A + B + C )'s work in one day = 13/240

A's alone work = 13/240 - 1/30 = 5/240 = 1/48

since A's alone work = 48days

Similarly .
for B's alone work = 13/240 - 1/40 = 7/240 days

since B's alone work = 34 + 2/7 days

And finally

c's alone work = 13/240 - 1/20 = 1/240

c's alone work = 240days

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Hope it helps you !!!

@Rajukumar111
$.$

Answer 2

Given that A + B can do a work in 20 days.

Then, (A + B)'s 1 - day work = (1/20) ------ (1)

Given that B + C can do a work in 30 days.

Then, (B + C)'s 1 - day work = (1/30) ------- (2)

Given that C + A can do a work in 40 days.

Then, (C + A)'s 1-day work = (1/40) -------- (3)

Adding (1) , (2), (3), we get

= > (A + B + B + C + C + A) 1-day's work = (1/20) + (1/30) + (1/40)

= > 2(A + B + C) 1 - day's work = (1 * 6 + 1 * 4 + 1 * 3)/120

= (6 + 4 + 3)/120

= 13/120.

Then, A + B + C = (13/240).

Now,

A's 1 - day work = (13/240) - (B + C)'s work

= (13/240) - (1/30)

= (5/240)

= (1/48).

A alone can complete the work in 48 days.

Now,

B's 1 - day work = (13/240) - (C + A)

= (13/240) - (1/40)

= 7/240.

B alone will complete the work in (240/7) or 34 (2/7) days.

Now,

C's 1 - day work = (13/240) - (A + B)

= (13/240) - (1/20)

= (1/240).

C alone can complete the work in 240 days.

Therefore:

A can complete the work in 48 days.

B can complete the work in (240/7) (or) 34 (2/7) days.

C can complete the work in 240 days.

Hope this helps!