Math, asked by snehachandarana, 9 months ago

please solve my question:

The denominator of a rational number is greater than its numerator by 3. If the number is increased by 16 and the denominator is decreased by 1,then the number obtained is 5/3, find the rational number.​

Answers

Answered by Anonymous
1

Answer:

Let the numerator of a rational number be x.

Therefore, denominator = x + 3

according to your question ,

x + 16 / x + 3 -1 = 5/3

or, x + 16 / x + 2 = 5/3

cross multiplication give

5 (x + 2) = 3 (x + 16)

or, 5x + 10 = 3x + 48

or, 5x - 3x = 48 - 10

or, 2x = 38

or, x = 38/2

or, x = 19

Hence, numerator = x = 19

& Denominator = x + 3 = 22

So , rational number = 19/22.

Answered by Anonymous
1

\bold\blue{Correct \ Question}

The denominator of a rational number is greater than its numerator by 3. If the numenator is increased by 16 and the denominator is decreased by 1, then the number obtained is 5/3, find the rational number.

\huge\purple{\underline{\underline{\pink{Ans}\red{wer:-}}}}

\sf{Rational \ number \ is \ \frac{19}{22}}

\sf\orange{Given:}

\sf{\implies{Denominator \ of \ a \ rational \ number}}

\sf{is \ greater \ than \ it's \ numerator \ by \ 3.}

\sf{\implies{If \ numenator \ is \ increased \ by \ 16 }}

\sf{and \ denominator \ is \ decreased \ by \ 1,}

\sf{then \ the \ number \ obtained \ is \ \frac{5}{3}}

\sf\pink{To \ find:}

\sf{Rational \ numbers \ are \ \frac{p}{q} \ form.}

\sf{The \ rational \ number.}

\sf\green{\underline{\underline{Solution:}}}

\sf{Let \ numenator \ be \ x \ and \ denominator}

\sf{be \ y.}

\sf{According \ to \ first \ condition}

\sf{\implies{y-x=3}}

\sf{\implies{-x+y=3...(1)}}

\sf{According \ to \ second \ condition}

\sf{\implies{\frac{x+16}{y-1}=\frac{5}{3}}}

\sf{\implies{3(x+16)=5(y-1)}}

\sf{\implies{3x+48=5y-5}}

\sf{\implies{3x-5y=-53...(2)}}

\sf{Multiply \ eq(1) \ by \ 3}

\sf{\implies{-3x+3y=9...(3)}}

\sf{Add \ equations \ (2) \ and \ (3)}

\sf{3x-5y=-53}

\sf{+}

\sf{-3x+3y=9}

_______________________

\sf{\implies{-2y=-44}}

\sf{\implies{y=\frac{-44}{-2}}}

\sf{\implies{y=22}}

\sf{Substitute \ y=22 \ in \ equation (1)}

\sf{\implies{-x+22=3}}

\sf{\implies{x=22-3}}

\sf{\implies{x=19}}

\sf{Rational \ number=\frac{x}{y}=\frac{19}{22}}

\sf\purple{\tt{\therefore{Rational \ number \ is \ \frac{19}{22}}}}

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