Question

please solve no 3 its urgent i'll sure I will mark as brainliest​

Answer 1

Answer:

$\large log_{10}12$

Step-by-step explanation:

$\large \text{we have to find value of 2+\dfrac{1}{2}log_{10}9-2log_{10}5 }\\\\\large \text{Here we will here three formula}\\\\\large log_{a}(x)^b=blog_{a}x \\\\\\\large log_{a}(m+n)=log_{a}m+log_{a}n \\\\\\\large log_{a}(\dfrac{m}{n}) =log_{a}m-log_{a}n$

$\large \text{rewrite 2 as log_{10}(10)^2 }\\\\\\\large log_{10}(100)+\dfrac{1}{2} log_{10}(3)^2-log_{10}25\\\\\\\large \text{using formula here we get}\\\\\\\large log_{10}(100\times3)-log_{10}25\\\\\\\large log_{10}(\dfrac{100\times3}{25} )\\\\\\\large log_{10}12\\\\\\\large \text{Thus we get answer log_{10}12 }$