Question

Please solve no.3 with easy steps.

Answer 1

given,
AC=18cm

AM=14cm

AN=6cm

BL=4cm

DM=12cm

EN=9cm

MC = AC-AM = 18-14 = 4cm

BL,DM,EN is perpendicular to AC

such that,

BL||DM||EN

area of ABC=1/2 * base * height
=1/2 * AC * BL
=1/2 * 18 * 4
=36cm²

area of AEN=1/2 * base * height
=1/2 * AN * EN
=1/2 * 6 * 9
= 27cm²

area of DMC=1/2 * base * height
=1/2 * MC * DM
=1/2 * 4 * 12
=24cm²

area of ENDM= half of the sum of the parallel sides * height
=a+b/2 * h
=DM+EN/2 * DM
= 12+9/2 * 12
= 21/2 * 12
=126 cm is

area of Pentagon= ar(ABC)+ar(AEN)+ar(DMC)+ar(ENDM)
=36cm²+27cm²+24cm²+126cm²
=213cm²

THE ANSWER MAYBE CORRECT.

HOPE U CAN UNDERSTAND