please solve no 41 to be brainliest
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- let "r" be money with raman and "k" is money with kamal
- given ram has money which is equal to 3 times of kamal i.e, r=3k------->1
- after raman gave 750 to kamal then kamal will have 2 thimes than raman i.e,(k+750)=2(r-750)------------>2
- On solving 1 and 2 we get k=450 and r=1350
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Let the amount of money Kamal initially having is ₹x and Raman initial money be ₹3x
As per the question,
Raman's money= (3x-750)
Kamal's money= (x+750)
x+750 = 2(3x-750)
x+750 = 6x-1500
750+1500 = 6x-x
2250 = 5x
2250/5 = x
x = 450
Therefore,
Kamal's initial money is ₹450
Raman's initial money is 3*450 = ₹1350
As per the question,
Raman's money= (3x-750)
Kamal's money= (x+750)
x+750 = 2(3x-750)
x+750 = 6x-1500
750+1500 = 6x-x
2250 = 5x
2250/5 = x
x = 450
Therefore,
Kamal's initial money is ₹450
Raman's initial money is 3*450 = ₹1350
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