Please solve no. 5
Chapter of Linear equations
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Answered by
1
hiii!!!
here's ur answer...
given that the sum of two numbers is 80 and the greater no. exceeds twice the smaller no. by 11.
let the smaller no.be x
therefoe the greater no. will be 2x + 11.
hence, x + 2x + 11 = 80
==> 3x + 11 = 80
==> 3x = 80 - 11
==> 3x = 69
==> x = 69/3
==> x = 23
therefore, the smaller no. is = x
= 23
greater no. = 2x + 11
= ( 2 × 23 ) + 11
= 46 + 11
= 57
VERIFICATION:-
= 23 + 57
= 80
hence verified
hope this helps u..!
here's ur answer...
given that the sum of two numbers is 80 and the greater no. exceeds twice the smaller no. by 11.
let the smaller no.be x
therefoe the greater no. will be 2x + 11.
hence, x + 2x + 11 = 80
==> 3x + 11 = 80
==> 3x = 80 - 11
==> 3x = 69
==> x = 69/3
==> x = 23
therefore, the smaller no. is = x
= 23
greater no. = 2x + 11
= ( 2 × 23 ) + 11
= 46 + 11
= 57
VERIFICATION:-
= 23 + 57
= 80
hence verified
hope this helps u..!
Anonymous:
thank you very much for brainliest
but he or she said u to mark his or her ans as brainliest
Answered by
1
let the smaller number be y
let the greater number be x
given sum of the two numbers=80
=>x+y=80 ......................................(1)
the greater number exceeds twice the smaller number by 11
=> x-2y=11 ....................................(2)
subtacting (2) from (1)
x+y-(x-2y)=80-11
x+y-x+2y=69
3y=69
y=23
=>x= 57
:. the numbers are 57 and 23
let the greater number be x
given sum of the two numbers=80
=>x+y=80 ......................................(1)
the greater number exceeds twice the smaller number by 11
=> x-2y=11 ....................................(2)
subtacting (2) from (1)
x+y-(x-2y)=80-11
x+y-x+2y=69
3y=69
y=23
=>x= 57
:. the numbers are 57 and 23
hope it helped you
mark me as brainliest if my answer helped you
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