please solve no 6 dum hai toh
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Area of trap. ABCH=1/2*(sum of ll sides)*h
=1/2*(5+11)*4=16*2=32cm^2
Hence Area of trap. DEFG will be = area of ABCH
=>Area of trap. DEFG = 32cm^2
Now,
Area of rect. CDGH = l*b
=11*5=55cm^2
Now required Area of octagon ABCDEFGH is = 32+32+55= 119cm^2
Hope you like it.
BRAINLIEST answer
Area of trap. ABCH=1/2*(sum of ll sides)*h
=1/2*(5+11)*4=16*2=32cm^2
Hence Area of trap. DEFG will be = area of ABCH
=>Area of trap. DEFG = 32cm^2
Now,
Area of rect. CDGH = l*b
=11*5=55cm^2
Now required Area of octagon ABCDEFGH is = 32+32+55= 119cm^2
Hope you like it.
BRAINLIEST answer
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