Question

please solve
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Answer 1

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Given relation is

$C = \frac{5 F- 160}{ 9}$

$on \: putting \: F \: = 104°$

We Get

$C = \frac{5 \times 104 - 160}{9}$

$⇒C = \frac{520 - 160}{9}$

$⇒C = \frac{360}{9}$

$= 40$

Hence the required temperature is 40° C

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