Question

please solve........no spam....​

Answer 1

Step-by-step explanation:

This problem can be solved by using the concept of similarity of the triangles.

I hope It was helpful to you

Answer 2

=> HOPE IT HELPS YOU SIS...

Given that X divides PQ in 2:1

= QX = 2/3 × PQ -----(1)

Similarly, Y divides QR in 2:1

= RY = 2/3 × QR -----(2)

In ∆PYQ,

PY² = PQ² + QY²

PY² = PQ² + (2/3 × QR)²

9PY² = 9PQ² + 4QR² ----(3)

In ∆XQR,

XR² = XQ² + QR²

XR² = (2/3 × PQ)² + QR²

XR² = 4/9 × PQ² + QR²

9XR² = 4PQ² + 9QR² ----(4)

On adding (3)+(4), we get

9(PY² + XR²) = 13(PQ² + QR²)

9(PY² + XR²) = 13PR² hence proved..

Thanks and Regards behna.