Question

Please solve on paper with method ​

Answer 1

=> (a+b+c). = 0

=> (a+b+c)³ = 0³

=> a³+b³+c³+3(a+b)+3(b+c)+3(a+c) = 0

=> a³+b³+c³ = -3(a+b)-3(b+c)-3(a+c)

=> a³+b³+c³ = -3(a+b+b+c+a+c)

=> a³+b³+c³ = -6(a+c+c)

=> a³+b³+c³ = -6(0)

=>a³+b³+c³ =0