please solve physics 11
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zero metres
Explanation:
t=√x+3
⇒√x=t-3
⇒x=(t-3)²
Differentiate with respect to t
dx/dt=2(t-3) ( Math help : d/dx (x-a)^n = n(x-a)^n-1)
dx/dt is nothing but velocity(v)
therefore, v=2(t-3),
Given v=0
⇒2(t-3)=0
∴t=3 seconds
substitute it in given equation,
3=√x+3
√x=0
x=0 m
Therefore its displacement is zero metres.
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