Question

please solve please please ​

Answer 1

Answer:

here you go

cases can be internal divison,external division

keep that in mind

Answer 2

Solution:-

The end point of AB are A ( 5 , -6 ) and B ( -1 , 4 )

$\rm \therefore(x_1 = 5 \: \: \: , \: \: y_1 = - 6) \: and \: (x_2 = - 1,y_2 = 4)$

also

$\rm \implies \: m = 5 \: \: and \: \: n \: = 1$

Let the required point be p(x , y)

By section formula, we have

$\rm \: x = \dfrac{mx_2 + nx_1}{m + n} \: \: and \: \: y = \dfrac{my_2 + ny_1}{m + n}$

Puting the value on formula we get

$\rm \: x = \dfrac{5 \times - 1 + 1 \times 5}{5 + 1} \: \: and \: \: y = \dfrac{5 \times 4 + 1 \times - 6}{6}$

$\rm \: x \: = \dfrac{ - 5 + 5}{6} \: \: \: and \: y = \dfrac{20 - 6}{6}$

$\rm \: x \: = 0 \: \: and \: \: y = \dfrac{14}{6} = \dfrac{7}{3}$

hence required point is p( 0 , 7/3 )