Question

please solve please please please I will follow you and Mark you brainliest​

Answer 1

Answer:

hope it helps you

if yes then please mark me as brainliest!!

Answer 2

Answer:

here is your answer........

Step-by-step explanation:

(i) √2 , 1/3

p(x)=x^2-(sum of zerors)x+(product of zerors)

=x^2-(√2)x+(1/3)

=x^2-√2x+1/3

=x^2-√2x+1

(ii) 0 , √5

p(x)= x^2-(sum of zerors)x+(product of zerors)

=x^2-(0)x+(√5)

=x^2-√5

(iii) 1, 1

p(x)= x^2-( sum of zerors)x+(product of zerors)

=x^2-(1)x+(1)

=x^2-x+1

(iv) 1,4

p(x)=x^2-(sum of zerors)x+(product of zerors)

=x^2-(1)x+(4)

=x^2-x+4

Hope it help you.........☺️