Question

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Answer 1

Step-by-step explanation:

Hope it's helps you....

Answer 2

✞︎ Given :-

${x}^{2} - 7x + 10 = 0$

❦︎ To find :-

• The zeroes of the polynomial
• And to Verify the relation.....

✯︎ Solution :-

➪︎ ${x}^{2} - 7x + 10 = 0$

➪︎ ${x}^{2} - 2x - 5x + 10 = 0$

➪︎ $x(x - 2) - 5(x - 2) = 0$

➪︎ $(x - 2)(x - 5) = 0$

➪︎ $x = 2 \: or \: 5$

✰︎ Therefore the zeroes are 2 & 5

_____________________________________

᯽︎ Sum of zeroes = 2 + 5

= 7

➪︎ $\frac{ - \: co - efficient \: of \: x}{co - efficient \: of \: {x}^{2} }$

➪︎ $= \frac{ - ( - 7)}{1}$

➪︎ $sum \: of \: zeroes = 7$

᯽︎ Product of zeroes = 2 × 5

= 10

➪︎ $\frac{contant \: term}{co - efficient \: of \: {x}^{2} }$

➪︎ $\frac{10}{1}$

➪︎ $product \: of \: zeroes = 10$

❁︎ Hence verified .......✔️