Please solve Q. 10.
Ans.=60+20/27.
Lesson GP
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Hiii...
Now u can do it
.....
Now u can do it
.....
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ameyashrivastav:
the photo isnt complete i think
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Q10. Geometric Progression / Series. To find the sum of numbers in GP.
Series: 81, -27, 9, .... , -1/27
Geom. Series: a , a r , a r², a r³ , ..... , a r ⁿ⁻¹
=> a = 81. r = (-27/81) = -1/3
a r⁽ⁿ⁻¹⁾ = -1/27
=> r⁽ⁿ⁻¹⁾ = -1/ [27 * 81] = -1/[ 3³ * 3⁴ ]
= -1/3⁷ = (-1/3)⁽⁷⁾
= r⁷
So n - 1 = 7
n = 8.
Sum = a [ 1 - rⁿ ] / [ 1 - r ]
= 81 [ 1 - (-1/3)⁸ ] / [ 1 - (-1/3) ]
= 81 * (3⁸ - 1) / [ 3⁸ * 4 / 3 ]
= 3⁴ * (3⁸ - 1) / ( 3⁷ * 4 )
= (3⁸ - 1)/108 = 1640/27
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Much simpler solution
we don't need to find n, as the last term is given.
Series: 81, -27, 9, .... , -1/27
Geom. Series: a , a r , a r², a r³ , ..... , a r ⁿ⁻¹
=> a = 81. r = (-27/81) = -1/3
a r⁽ⁿ⁻¹⁾ = -1/27
=> r⁽ⁿ⁻¹⁾ = -1/ [27 * 81] = -1/[ 3³ * 3⁴ ]
= -1/3⁷ = (-1/3)⁽⁷⁾
= r⁷
So n - 1 = 7
n = 8.
Sum = a [ 1 - rⁿ ] / [ 1 - r ]
= 81 [ 1 - (-1/3)⁸ ] / [ 1 - (-1/3) ]
= 81 * (3⁸ - 1) / [ 3⁸ * 4 / 3 ]
= 3⁴ * (3⁸ - 1) / ( 3⁷ * 4 )
= (3⁸ - 1)/108 = 1640/27
=============================
Much simpler solution
we don't need to find n, as the last term is given.
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