Please Solve Q 2 & 3 I Will Mark U As Brainliest.
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(2)..sorting the list in ascending order
6, 8, 10, 10, 15,15, 15, 50, 80, 100, 120
there are 11 players...and median is the middle number of the sorted list....so median is 15.
mode is the number occuring most of the time in the list
so the mode is 15
mean=sum of the numbers/total numbers of the list
mean=(6+8+10+10+15+15+15+50+80+100+120)/11
=429/11=39
all the three are not same
(3)Arranging these weights in ascending order,
32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43,43,45, 47, 50
median=40
mode=38 and 43...both occuring 3 times
hence there are 2 modes
6, 8, 10, 10, 15,15, 15, 50, 80, 100, 120
there are 11 players...and median is the middle number of the sorted list....so median is 15.
mode is the number occuring most of the time in the list
so the mode is 15
mean=sum of the numbers/total numbers of the list
mean=(6+8+10+10+15+15+15+50+80+100+120)/11
=429/11=39
all the three are not same
(3)Arranging these weights in ascending order,
32, 35, 36, 37, 38, 38, 38, 40, 42, 43, 43,43,45, 47, 50
median=40
mode=38 and 43...both occuring 3 times
hence there are 2 modes
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