Please solve Q.4 and Q.5 of the image given.
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Let the original speed of the train=xkm/hr
Time= distance/speed
360/x-360/(x+5)= 48/60
360/x-360/(x+5)=4/5
360[1/x-1/(x+5)]=4/5
360×5/4[5/(x2+5x)]=1
450×5=x2+5x
x2+5x-2250=0
x=[-5±√(25+9000)]/2
=[-5±√(9025)]/2
= (-5±95)/2
= -50,45
X=45km/hr
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