Question

Please solve Q no. 11 i ii iii

Answer 1

Answer:

hii friend here is ur solution

(1) in tri ADB and tri CDE we have

angle ADB=angleEDC( verti. opp angle)

BD =DE ( given)

AD=DC( D is the midpoint of AC)

hence tri ADB is congruence to tri CDE

(2) in tri ABC and tri ECB we have

BC=BC (common)

AC = BE (proved above)

AB= EC (proved above)

hence triangle ABC is cong to tri ECB