Please solve Q no. 69
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in given fig
perimeter of fig= perimeter of rectangle + 4*permiter of arc of radius 2/perimeter of circle
perimeter of given fig=2*(20+10)+2*3.14+2
=60+12.56
=72.56
hope it helps you
Answered by
1
Answer:
56.6m
Step-by-step explanation:
Given :
To find the perimeter of the given figure,.
Solution :
Perimeter = 2 × (length of the rectangle - 2 × radius of the quadrant) + 2 × (breadth of the rectangle - 2 × radius of the quadrant) + 4 × length of the arc of quadrant
⇒ 2 × (20 - 2 × 2) + 2 × ( 10 - 2 × 2) + 4 × (πr)/2
⇒ 2 × ( 20 - 4) + 2 × (10 - 4) + 2 × π × 2
⇒ 2 × 16 + 2 × 6 + 4π
⇒ 32 + 12 + 4 × 3.14
⇒ 44 + 12.56 = 56.56 ≈ 56.6m
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