please solve q no. 7, 8 ,9 ,10
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ques9--1) in ∆ADC,Q is the mid point of AC such that PQ//AD
Therefore,P is the mid point of DC
So,DP=PC
2) Similarly,R is the midpoint of BC
therefore,PR=½BD(diagonal of a rectangle are equal so,BD=AC)
So,PR=½AC
Therefore,P is the mid point of DC
So,DP=PC
2) Similarly,R is the midpoint of BC
therefore,PR=½BD(diagonal of a rectangle are equal so,BD=AC)
So,PR=½AC
khushikesarwani20:
AC is the diagonal of rectangle ABCD..So ∆ADC=∆ABC
and,in ∆ADC P is the midpoint of DC
so,DP=PC
now,join BD..diagonal
in,∆ABC,R is the midpoint of BC..so BR=RC
now,join PR.. diagonal of rectangle PQRC
so,you can see that PR is half of BD
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