please solve q no 8 I will be
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in ∆ACD and ∆BDC
<ACD =<BDC(adding the equal angles)
CD=DC(common)
angle ADC= angle BCD(Given)
both the ∆ are congruent by ASA congruency condition..
then BC=AD(By cpct)
and angle A=B
<ACD =<BDC(adding the equal angles)
CD=DC(common)
angle ADC= angle BCD(Given)
both the ∆ are congruent by ASA congruency condition..
then BC=AD(By cpct)
and angle A=B
Answered by
1
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