please solve Q2 and Q3
Attachments:
Answers
Answered by
1
ans for ques 3 :-
according to theorem , ratio of areas of similar triangle is equal to the ratio of squares of the sides of triangle....
so,
arABC/arPQR = (1/3)square
= 1/9
Therefor ratio is equal to 1 : 9
according to theorem , ratio of areas of similar triangle is equal to the ratio of squares of the sides of triangle....
so,
arABC/arPQR = (1/3)square
= 1/9
Therefor ratio is equal to 1 : 9
adityamishra7672:
thanks bro if you find helpful make it brainliest.....
Similar questions
Social Sciences,
7 months ago
Science,
7 months ago
Science,
1 year ago
Physics,
1 year ago
Physics,
1 year ago