Question

please solve Qn no 8,9

Answer 1

$8. \\ \\ Let\ the\ two\ numbers\ be\ x\ and\ 3x. \\ \\ x + 3x = 4x = 124 \\ \\ x = \frac{124}{4} = \bold{31} \\ \\ 3x = 3 \times 31 = \bold{93} \\ \\ \therefore\ \bold{31}\ and\ \bold{93}\ are\ the\ numbers.$

$\\ \\ \\ 9. \\ \\ Let\ the\ numbers\ be\ x\ and\ 5x. \\ \\ 5x - x = 4x = 132 \\ \\ x = \frac{132}{4} = \bold{33} \\ \\ 5x = 5 \times 33 = \bold{165} \\ \\ \therefore\ \bold{33}\ and\ \bold{165}\ are\ the\ numbers.$

$\\ \\ \\ Thank\ you. \\ \\ \\ \#adithyasajeevan$

Answer 2

question 8

let the number be = x and y

x=3y

x+y=124

now put the value of x

3y +y=124

4y=124

y=124/4

y=31

now put value of y

x=3y

x= 3*31

x =91

the answer is [31,,91]

question 9

let two number = x and y

x =5y

x - y =132

5y-y =132

4y = 132

y = 132/4

y = 33

now add the value of y

x = 5y

x = 5*33

x = 165

so x and y =33,165