please solve qno. 20
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Sathwikabandari:
1:8:27?
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let there diameters are 1x 2x 3x units
then there radius are 1x/2,2x/2,3x/2
Then there areas are in ratio
(1/2)^2:(2/2)^2:(3/2)^2
=1/4:1:9/4
=1:4:9
then there radius are 1x/2,2x/2,3x/2
Then there areas are in ratio
(1/2)^2:(2/2)^2:(3/2)^2
=1/4:1:9/4
=1:4:9
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