Question

PLEASE SOLVE QS FAST AS POSSIBLE
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Answer 1

Answer:

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Answer 2

Rewrite, p2x2+p2x−q2x−q2=0

⇒ p2x(x+1)−q2(x+1)=0

⇒ (x+1)(p2x−q2)=0

⇒ If x−1=0  or (p2x−q2)=0

⇒ x=−1 or x=p2q2

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