Please solve que. No. 18 fast
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Answer:
Step-by-step explanation:
Donia:
In triangle DEB and BCA
Angle E is equal to angle C as they are 90°
Angle B is equal to angle A due to alternate interior angles
By AACriterion both the above mentioned triangle are similar
DE/BC=BE/CA=DB/BA
Therefore AC/BC=BE/DE
Hope this will help u
But it is not given that AC||BC
i think v shud assume it
Answered by
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In the given figure angle DBE + angle BDE = 90. .......(1) ( bcz angle BDE and angle DBE are opposite angles....remember the thoerem external angle is equal to sum of other to internal angle in a traingle)
angle DBE + angle EBC = 90........(2)
subtract (2) from (1)
we get ,
angle DBE - angle DBE + angle BDE - angle EBC = 90-90
angle BDE. = angle EBC. ........(3)
angle DEB = angle ACB. ...........(4)
By AA rule ∆ ACB similar to ∆ DEB
So ,
DE/AC = BE/BC
by rearringing the terms ,
AC.BE = DE.BC
BE/DE = AC/BC
Hence proved. ☺
angle DBE + angle EBC = 90........(2)
subtract (2) from (1)
we get ,
angle DBE - angle DBE + angle BDE - angle EBC = 90-90
angle BDE. = angle EBC. ........(3)
angle DEB = angle ACB. ...........(4)
By AA rule ∆ ACB similar to ∆ DEB
So ,
DE/AC = BE/BC
by rearringing the terms ,
AC.BE = DE.BC
BE/DE = AC/BC
Hence proved. ☺
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