Question

Please solve Que3-(4) using D=b²-4ac.
*THE BEST EXPLAINED ANSWER WOULD BE MARKED AS BRAINLIEST.
*THE SOLUTION MUST BE DONE BY USING FORMULA THEN ONLY I WILL MARK IT AS BRAINLIEST.
*WRONG ANSWER OR SOLUTION WITHOUT FORMULA WOULD BE REPORTED.
DO YOUR BEST.
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Answer 1

Given Equation is x^2 + 7(3 + 2k) - 2x(1 + 3k) = 0.

On comparing with ax^2 + bx + c = 0, we get

a = 1, b =-2(1 + 3k), c = 7(3 + 2k)

Given that the equation equal roots.

D = b^2 - 4ac = 0

= > (-2(1 + 3k))^2 - 4(1)(7(3 + 2k)) = 0

= > 4(1 + 3k)^2 - 4(21 + 14k) = 0

= > 4(1 + 9k^2 + 6k) - 84 - 56k = 0

= > 4 + 36k^2 + 24k - 84 - 56k = 0

= > 36k^2 - 32k - 80 = 0

= > 4(9k^2 - 8k - 20) = 0

= > 9k^2 - 8k - 20 = 0

= > 9k^2 - 18k + 10k - 20 = 0

= > 9k(k - 2) + 10(k - 2) = 0

= > (9k + 10)(k - 2) = 0

= > (9k + 10) = 0, (k - 2) = 0

= > k = -10/9, k = 2.


Therefore the value of k = 2, -10/9.


Hope this helps!