please solve ques 27 both parts. i am waiting so solve it as soon as possible
Attachments:
Answers
Answered by
1
Answer:
Step-by-step explanation:
Attachments:
umikarao:
Hey sorry i dont know the ans of second part
Pls mark as brainliest and rate the ans
second part: Diagram- Light house in the middle.. ships on either side... Draw a triangle. Draw a height from the top vertex. THIS HEIGHT IS OUR LIGHT HOUSE. Top vertex= A, Base=BC. The height like straight line = AD. Hope the diagram is clear. Base 'BC' is the distance between the ships which is 200 [(root3+1)/root3]..
(The angle of depression is the top angle. By angle property of parallel line we obtain the bottom angles also similar)
Now, Tan 45 = AD/CD... AD= light house height... CD = AD/Tan 45 ... CD= AD ..(i)
Tan 60 = AD/BD... BD = AD/Tan 60 = AD/root 3.. BD = AD/root3 ...(ii)
BD + CD = BC = base = distance between the ships
Hence, 200 [ (root3+1)/root3] = AD + AD/root3 200 [ (root3+1)/root3] = [ADroot3 + AD]/root3 ... (took LCM in RHS)
200 [ (root3+1)/root3] = AD [ (root3+1)/root3]... Closely observe the LHS and RHS, we can find that AD = 200. Hence, height of light house = 200m
Answered by
1
please mark it as brain list answer
Attachments:
Similar questions