Question

Please solve ques in the attachment

Answer 1

Answer:

∠AOB = 105º, ∠AMB = 127.5º

Step-by-step explanation:

AP and BP are tangent of a circle.

⇒ ∠PAO and ∠PBO are 90º

All angles in a quadrilateral add up to 360º

∠AOB = 360 = 75 - 90 - 90

∠AOB = 105º

Angles at a point add to 360º

Reflect ∠AOB = 360 - 105 = 255º

Angles at the centre of a centre is twice the angle at the circumference:

∠AOB (reflect) = 2 ∠AMB

∠AMB = 255 ÷ 2

∠AMB = 127.5º

Answer: ∠AOB = 105º, ∠AMB = 127.5º