Question

Please solve ques no. 26th

Ch-2 Polynomial

Class 10th

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Answer 1

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let p(x) = ax² + bx + c

Given zeros are reciprocal of each other

Thus let the zeros be w and 1/w

Then

$= > \alpha + \beta = \frac{ - b}{a}$
Replacing zeros

=> w + 1/w = -b/a

=> (w² + 1)/w = -b/a --------(1)

Similarly

$= > \alpha \beta = \frac{c}{a}$

Replacing zeros

=> w(1/w) = c/a

=> a = c ------(2) <<<<< Answer

Use (2) in (1)

=> (w² + 1)/w = -b/c <<<<<<<< Answer

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Hope this helps ✌️