CBSE BOARD X, asked by pranjal7, 1 year ago

Please solve ques no 30

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pranjal7: I don't know how to make figures if both angle of elevation and elevation r given. Please tell me in detail.

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Answered by rohitkumargupta

HELLO DEAR,

$in \: triangle \: \:( abc) \\ < d = 60 \\ \tan(60 ) = \frac{ab}{bd} \\ = > \sqrt{3} = \frac{60}{x} \: \: \: \: \: \: \: (ab = 60meter \: \: \: bd = x \\ = > x = 60 \sqrt{3} \\ = > x = \frac{60 \times \sqrt{3} }{ \sqrt{3} \times \sqrt{3} } \\ = > x = 20 \sqrt{3} \\ = > in \: triangle \: \: \: aec \: \: angle \: c = 30 \\ = > \tan(30) = \frac{ae}{ec} \\ = > \frac{1}{ \sqrt{3} } = \frac{ae}{20 \sqrt{3} } \\ = > ae = 20meter \\ = >$
horizontal distance between building and lamp post= 20√3

b. the height of lamp post= 60-20=40 m

therefore difference between height=20 m

I HOPE ITS HELP YOU DEAR,
THANKS

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pranjal7: Where is the figure?

pranjal7: I have not understood how to make figure. After making fig I can solve the ques. But I face difficulty in making fig of such ques. Can u explain me how to make figures?

rohitkumargupta: wait

rohitkumargupta: dear

rohitkumargupta: i hope here u understand with the help of fig my writing is so bad then plz compromise dear

Answered by tnwramit1

This is ur ans hope it will help you in case of any doubt comment below

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tnwramit1: tnx for brainliest

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