Question

Please solve ques.no. (b)
[Hint: Answer is 17]

Answer 1

Answer:

the answer is 17

Step-by-step explanation:

first use BODMAS

Answer 2

Find the discriminant of the following equations.

• 2${ \tt \cfrac{1}{x + 2 } + \cfrac{1}{x - 2} = 2}$

Taking LCM of x+2 and x-2= (x+2)(x-2).

${\implies \tt \cfrac{x - 2 + x + 2}{(x + 2 )(x - 2) } = 2}$

${\implies \tt \cfrac{x \: \cancel{- 2 }+ x \: \cancel{+ 2}}{ {x}^{2} - {2}^{2} } = 2}$

${\implies \tt \cfrac{2x}{ {x}^{2} - 4 } = 2}$

${ \implies\tt 2x = 2( {x}^{2} - 4) }$

${ \implies\tt 2x = 2{x}^{2} - 8 }$

${\implies \tt2 {x}^{2} - 2x - 8 = 0 }$

$\sf a=2,b=-2 and c=-8$

$\bf{~~Discriminant = {b}^{2} - 4ac}$

$\sf{~~~Discriminant = {( - 2)}^{2} - (4 \times 2 \times ( - 8))}$

$\sf{~~~~Discriminant = 4 - (8 \times - 8})$

$\sf{~~~~~Discriminant = 4 - ( - 64)}$

$\sf{~~~~~~Discriminant = 4 + 64}$

$\sf{~~~~~~~Discriminant = 68}$

$\underline{\boxed{\pink{\sf{Hence\ Discriminant= 68}}}}$