please solve question 1 ,7 , 8 ,9 , it is sooo ugent dooo it fast ( 1 question toh jaroor karnaa please )
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Step-by-step explanation:
7) root 2 x square -3x- 2root 2=0 is in the form-
ax square+bx+c=0
multiply root 2x square and 2root2 we get 4 (a*c)
root 2 x square -4x+x- 2root 2=0
√ 2 x(x-2√2) + 1(x-2√2)=0
(√2x+1) (x-2√2)=0
x=2√2 and -1/√2
roots of the above equation are 2√2 and -1/√2
krishna200notout:
do the first one please
sure
do it fast please
x square -4 root 2x+6=0
x2−2√2x−2√2x+8−2=0
=>x∗(x−2√2)−2√2(x−2√2)−2=0
=>(x−2v2) whole square−√2 square=0
=>(x−2√2) whole square=√2 square
=>(x−2√2)=±√2
=>x∗(x−2√2)−2√2(x−2√2)−2=0
=>(x−2v2) whole square−√2 square=0
=>(x−2√2) whole square=√2 square
=>(x−2√2)=±√2
i hope you will be able to understand my answer and sorry for the delay.
ok
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