Question

please solve question 10

Answer 1

Taking LHS and applying R2->R2-2R1 and R3->R3-3R1 you get x+y x x
3x+2y 2x 0
7x+5y 5x 0
Now expand along c3
X | 3x+2y 2x
7x+5y 5x |
Now solving
X[5x(3x+2y)-2x(7x+5y)]
Solving this equation you get the value x^3

Answer 2

done ... too easy ...