Question

please solve question 10 please ​

Answer 1

Solution ◕‿◕

Given ==>

▪︎ p(x) = x⁵-3x⁴-ax³+3ax²+2ax+4

▪︎ g(x) = x-2

Need to find ==>

value of a

Explanation ==>

p(x)= x⁵-3x⁴-ax³+3ax²+2ax+4

g(x) = x-2=0

= x=2

Put x=2 in p(x)

p(x) = x⁵-3x⁴-ax³+3ax²+2ax+4

= (2)⁵-3×(2)⁴-a×(2)³+3a×(2)²+2a(2)+4=0

= 32-3×16-a×8+3a×4+2a×2+4=0

= 32-48-8a+16a+4=0

= -16+8a+4=0

= 8a=-4+16

= 8a= 12

$a = \frac{12}{8} \\ \\ = a = \frac{3}{2}$

So, value of a is 3/2

Answer 2

Answer:

a=3

Step-by-step explanation:

factor = x-2

so, x-2=0

    x=2

x=2 is a zero of polynomial : x^(5)-3x^(4)-ax^(3)+3ax^(2)+2ax+4

put the value of x in the equation:  x^(5)-3x^(4)-ax^(3)+3ax^(2)+2ax+4

                                                      =2^(5)-3*2^(4)-a*2^(3)+3a2^(2)+2a*4+4

                                                      =32-3*16-a*8+3a*4+8a+4

                                                       =32-48-8a+12a+4

                                                       = -16+4a+4

                                                       = -12 +4a

If x=2 is a zero of polynomial  x^(5)-3x^(4)-ax^(3)+3ax^(2)+2ax+4 so -12 +4a

must also be zero.

-12+4a=0

4a=0+12

a=12/4

a=3