please solve question 11 nd 15
Attachments:
lsb10:
DEAR IT IS A QUESTION FROM OPTIONAL EXERCISE NCERT
i know... bt school mein kuch samajh ni aaya....
OK I AM PROVIDING THE ANSWER
okk thanks
BUT PLEASE MARK IT AS THE BRAINLIEST
PLEASE
okk no tnsn yr
Answers
Answered by
1
QUESTION 14
Solution: Number of rungs can be calculated as follows:
2.5 x 100 cm ÷ 25 + 1
= 2.5 x 4 + 1
= 10 + 1 = 11
Now, we have; a = 25, a11 = 45 and n = 11
So, d can be calculated as follows:
a11 = a + 10d
Or, 45 = 25 + 10d
Or, 10d = 45 – 25 = 20
Or, d = 2
Now, total length of wood shall be equal to the sum of 11 terms;
=11/2(2*25+10*2)
=11(25+10)
=11*35
=385
it's ok yaar....
tnx
okk no problem
block / report user
lsb10
We have; a = 20, d = - 1 and Sn = 200
We know;
sum of n termsThus, n = 16 and n = 25
If number of rows is 25 then;
a25 = 20 + 24 x (- 1)
= 20 – 24 = - 4
Since; negative value for number of logs is not possible hence; number of rows = 16
a16 = 20 + 15 x (- 1)
= 20 – 15 = 5
Thus, number of rows = 16 and number of logs in top rows = 5
lsb10
We have; a = 20, d = - 1 and Sn = 200
We know;
sum of n termsThus, n = 16 and n = 25
If number of rows is 25 then;
a25 = 20 + 24 x (- 1)
= 20 – 24 = - 4
Since; negative value for number of logs is not possible hence; number of rows = 16
a16 = 20 + 15 x (- 1)
= 20 – 15 = 5
Thus, number of rows = 16 and number of logs in top rows = 5
PLEASE MARK IT AS BRAINLIEST , I NEED IT
Solution: Here, a = 1, d = 1 and a49 = 49
As per question;
S(x-1) = S49 - Sx ……….(1)
10 arithmetic progression exercise solution
Similarly,
10 arithmetic progression exercise solution
Similarly,
10 arithmetic progression exercise solution
After substituting the values of Sx-1, S49 and Sx in equation (1), we get;
As per question;
S(x-1) = S49 - Sx ……….(1)
10 arithmetic progression exercise solution
Similarly,
10 arithmetic progression exercise solution
Similarly,
10 arithmetic progression exercise solution
After substituting the values of Sx-1, S49 and Sx in equation (1), we get;
X=35
tnxx
srry bt no one else has commented... so i cant
thanks
Similar questions