PLEASE SOLVE QUESTION 12.(12 Not 11)
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Answer:
a²+c² = ab + cd
ab+cd = b² + d²
=> (a²+c²)×(b² + d²) = (ab+cd) × (ab + cd)
=>. a²b²+a²d² + b²c²+ c²d² = a²b²+abcd + abcd +c²d²
=> a²b²+a²d² + b²c²+ c²d²-a²b²-c²d² =2abcd
=>a²d² + b²c² = abcd
2
Hence,proved
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