Math, asked by ujjwalraj162004, 10 months ago

PLEASE SOLVE QUESTION 12.(12 Not 11)

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Answers

Answered by namrata10101

1

Answer:

a²+c² = ab + cd

ab+cd = b² + d²

=> (a²+c²)×(b² + d²) = (ab+cd) × (ab + cd)

=>. a²b²+a²d² + b²c²+ c²d² = a²b²+abcd + abcd +c²d²

=> a²b²+a²d² + b²c²+ c²d²-a²b²-c²d² =2abcd

=>a²d² + b²c² = abcd

2

Hence,proved

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