Please solve question 13..
Answers
Step-by-step explanation:
1. x = 50°
2. x = 100°
3. x = 80°
4. x = 50°
5. x = 20°
6. x = 45°
Hope it helps
Solution i :-
In the given question it is an isosceles ∆
Property of isosceles ∆ :- If two sides are equal sides opposite angles are also equal .
Here , x is one of the opposite so othe other opposite angle also will be x .
Now , using angle sum property
→ 80° + x + x = 180°
→ 2x = 180° - 80°
→ 2x = 100°
→ x = 100°/2
→ x = 50°
Solution ii :-
In the given it is also a isosceles ∆ .
Now , using the same properties
→ x + 40° + 40° = 180°
→ x = 180° - 80°
→ x = 100°
Solution iii :-
Let the other angle be y Here , in the given figure Using , straight line property
→ y + 130° = 180°
→ y = 180° - 130°
→ y = 50°
Now , using angle sum property
→ x + y + y = 180°
→ x + 50° + 50° = 180°
→ x = 180° - 100°
→ x = 80°
Solution iv :-
Let us take ∆₁ from the given figure.
Here , ∆₁ is a isosceles ∆ with side's opposite angle 50°
Now , using angle sum property and finding the other angle
Let the other angle be y
→ 50° + 50° + y = 180°
→ 100° + y = 180°
→ y = 180° - 100°
→ y = 80°
Hence , other angle is 100°
Now , here ∆1 & ∆2 are connected each other. The ∆'s are connected to interior opposite angles .
Here , interior opposite angles are always equal . So , y = 100° = other angle in ∆₂
The ∆₂ is also a isosceles ∆
Now , using angle sum property
→ x + x + 80° = 180°
→ 2x = 180° - 80°
→ 2x = 100°
→ x = 100°/2
→ x = 50°
Solution v :-
Here , in the given figure there are two ∆'s (∆₁ & ∆₂)
There are two isosceles ∆'s
Let ∆₁'s sides opposite angle be y
Using straight line property
→ 140° + y = 180°
→ y = 180° - 140°
→ y = 40°
Let one angle of ∆₂ be z
Now , using straight line property
→ 40° + z = 180°
→ z = 140°
Now , using angle sum property
→ x + x + 140° = 180°
→ 2x = 40°
→ x = 40°/2
→ x = 20°
Solution vi :-
Here , given triangle is a right angle isosceles ∆ Now , using angle sum property
→ x + x + 90° = 180°
→ 2x = 90°
→ x = 90°/2
→ x = 45°