Question

Please solve question 17

Answer 1

Answer:

In ∆ACB and ∆CDA.

∠ACB=∠CDA(given)

∠CAD=∠CAD(common)

So, ∆ACB∼∆CDA(S. S Prop)

Now, since ∆ACB∼∆CDA

So, AC/AD = AB/AC

=6/3=AB/6

=>AB=12

Hope you got your answer.