Physics, asked by singhayushi2005, 10 months ago

Please solve question 2

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Answered by pradhyunmahasivabhat
1

Answer:

(a) during 2 to 5 seconds and 7 to 9 seconds

(b) during 5 to 7 seconds

Explanation:

(c) The obj is moving at greater speed during the time 7 to 9 sec.

This is because:

Speed during CD  =    400m/2s  = 200m/s

Speed of BC = 0/2    = 0m/s

Speed of AB = 300m/3s    =     100m/s

Since the speed during 7 to 9 sec is more

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