Question

Please solve question 21 in notebook ...remember in notebook please Request

Answer 1

hope this will be helpful

Answer 2

Radius of big circle = 6cm
As points QR trisect the diameter PS
Therefore, PQ= QR= RS= 12/3 = 4cm
Radius of circle of diameter QS= 4cm
Radius of circle of diameter PQ= 4/2 = 2cm
Area of semicircle of big circle = 0.5 × 22/7 × 6×6=56.58cm

Area of semicircle of diameter QS = 0.5 × 22/7× 4 ×4 = 25.14cm

Area of semicircle of diameter PQ = 0.5× 22/7× 2× 2=6.28cm
Area of shaded region = area of big semicircle + area of semicircle of diameter PQ – area of semicircle of diameter QS

Ar. Of shaded region = 56.58+6.28–25.14
= 37.72cm (ans)

Hope it helps
Claculation mistake ho sakti hai bas par method theek hai