Question

please solve question 29. it's of 4 marks 12th standard maths. please solve on a paper step by step and upload picture thanks​

Answer 1

$\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }$

To get the point of intersection, we have to solve the equation of line Y+x=2and parabola y2=x. 

On solving them we find the coordinates of points of intersection as (4,−2) and (1,1). Drawing perpendiculars from these points on y-axis, we obtain the coordinate as (0,1) and (0,−2).

Thus, required area =∫−21(2−y−y2)dy=[2y−2y2−3y3]1−−2

=(2−21−31)−(4−−24+83)

=2−65+6−38=8−621=627

=29sq.units.

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Answer 2

Answer:

\Large\mathtt\green{ }\huge\underline\mathtt\red{Answer : }

Answer:

To get the point of intersection, we have to solve the equation of line Y+x=2and parabola y2=x.

On solving them we find the coordinates of points of intersection as (4,−2) and (1,1). Drawing perpendiculars from these points on y-axis, we obtain the coordinate as (0,1) and (0,−2).

Thus, required area =∫−21(2−y−y2)dy=[2y−2y2−3y3]1−−2

=(2−21−31)−(4−−24+83)

=2−65+6−38=8−621=627

=29sq.units.

_________________________

Step-by-step explanation:

mark above as Brainlist please