Please solve question 30 on applications of AP ( Arithmetic Progression )
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Step-by-step explanation:
let the three angles in AP be x, x+a ,x+2a
then,
x +2a = 3(x)
x +2a = 3x
2x = 2a
x = a
so, x + x+a + x+2a = 180°
x + x + x + 3(x) = 180
3x + 3x = 180
x = 30
hence, the angles be 30 , 60, 90
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