Math, asked by Shaambhavi, 1 year ago

please solve question 5

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Answered by vimal217

angle AoB=65°
angle BAO=35°
AOB+BAO+ABO=180
HENCE ABO=180-100
ABO=80
ABO+ADB+BAD=180
75+80+ADB=180
ADB=25

ADB=ABC
ABC=25
BAC=BCD
BCD=40
BDC=180-65
115=BDC

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