please solve question 5.
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Given: ABCD is a cyclic quadrilateral; ∠A=2x+4; ∠C=4x+64
To find: Value of x
Solution: ∠A+ ∠C=180°(Opposite angles of a cyclic quadrilateral are supplementary)
Hence, (2x+4)+(4x+64)=180°
2x+4+4x+64=180°
6x+68=180°
6x=112°
x=112°/6
x=18.66°(approx)
Hence, ∠BAD=2(18.66)+4=41.32°
∠BCD=4(18.66)+64=138.64°
Hope it helps<3
Pls mark the brainliest if it does
To find: Value of x
Solution: ∠A+ ∠C=180°(Opposite angles of a cyclic quadrilateral are supplementary)
Hence, (2x+4)+(4x+64)=180°
2x+4+4x+64=180°
6x+68=180°
6x=112°
x=112°/6
x=18.66°(approx)
Hence, ∠BAD=2(18.66)+4=41.32°
∠BCD=4(18.66)+64=138.64°
Hope it helps<3
Pls mark the brainliest if it does
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