Question

please solve question 5,6,&7 for me..........

Answer 1

HLO MATE ✋✋
Simran Here !!!
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5)...
The radius and height of a cylinder is in ratio 5:7
Let the Radius be = 5x
& Height of cylinder = 7x

Volume of cylinder = 550cm^3

So,
$volume \: of \: cylinder \: = \pi {r}^{2}h$
550 = 22/7 × (5x)^2 (7x)
550 = 22/ 7 × 25x^2 × 7x
550 = 22 × 5x × 5x × x
550 = 550x^3
x^3 = 1
x = 1 cm
So ,Radius of cylinder is 5cm
Height of cylinder is 7cm....✔

⭐⭐⭐⭐
6) Thickness of hollow cylinder = 2cm
Length of cylinder(h) = 35cm
Inner Radius of a cylinder(r) = 12cm
Outer Radius of cyliner(R) = 12 + 2 = 14cm

Now , Volume of metal required = Volume of whole cylinder - Volume of hollow cylinder

=> pi(R)^2 h - pi(r)^2 h
=> pi ( R^2 - r^2) h
=> 22/7 [(14)^2 - (12)^2] 35
=> 22/7 [ 196 - 144] 35
=> 22/7 × 52 × 35
=> 5720 cm^3

Hence,The volume of metal required is 5720cm^3✔
⭐⭐⭐⭐
7)
Length of rectangular sheet = 33cm
Width of rectangular sheet = 32cm

Length of rectangular sheet = circumference of circle

33cm = 2pir
33cm = 2 × 22/7 × r
r = 231/44
r = 5.2cm

Now Capacity of volume of cylinder = pir^2h
= > 22/7x 5.25 × 5.25 × 32
=> 19404/7
=> 2272cm^3

Hence,The capacity or volume of cylinder is 2272cm^3...✔
________________________________
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Answer 2

Radius = 5x
Height= 7x
Vol. of cylinder=pie r square
550=22/7×5x×5x×7x
550=22×5x×x
550=550 xcube
550/550=x cube
1 = x cube
x =
$\sqrt[3]{1 {}^{3} }$
x=1
Radius =5x
=5×1
=5cm
Height=7×1=7cm



6. B = 25cm
H= 35cm
Inner radius= 12cm
Outer radius= 12+2 = 14
Volume of inner part=
$\pi \: r {}^{2} h$
=22/7 ×12×12×35
=22×12×12×5=15835cm square
Volume of outer part =
$\pi \: r {}^{2} h$
22/7 ×14×14×35
=22×2× 14 ×35
=21565cm square
Total volume=
$\pi \: r {}^{2} h \: + \pi \: r {}^{2} h$
$\pi \: h \: (r {}^{2} - r {)}^{2}$
= 22/7 × 35 × ( 14 square - 12 square)
= 110( 196 -144)
= 110 ( 52)
=5120