Question

please solve question a) by step by step​

Answer 1

Step-by-step explanation:

let the numbers be:-

a/r,a,ar

then according to question

a/r+a+ar=19 .....(1)

a/r×a×ar=216 .....(2)

now from (2) we can get a^3 =216

i.e. a=6

and now put a=6 in (1) we get :-

6/r+6+6r=19

6r^2 +6r+6=19r

6r^2 -13r+6=0

6r^2 -9r-4r+6=0

3r(2r-3) -2(2r-3)=0

(3r-2)(2r-3)=0

since,r=3/2,2/3.

since three numbers are :-

6/2/3,6,6×2/3

9,6,4 .

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