Question

Please solve question both parts of Qno. 3

Answer 1

hey mate.
here's the solution

cot^2 theta - 1/sin^2 theta

= (cos^2 theta -1)/sin^2 theta

As cos^2 theta -1 = -sin^2 theta


NOW,refer to attachment

Answer 2

Answer:

(a) -1

(b) 5/2

Step-by-step explanation:

(a)

Given cot²θ - (1/sin²θ)

⇒ cot²θ - cosec²θ

We know that cosec²θ - cot²θ = 1 (or) cot²θ - cosec²θ = -1

⇒ -1.

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(b)

Given sinθ = cosθ

⇒ sinθ = sin(90-θ)

⇒ θ = 90 - θ

⇒ θ = 45.

Now,

⇒ 2tanθ + cos²θ

⇒ 2tan(45) + cos²(45)

⇒ 2(1) + (1/√2)²

⇒ 2 + 1/2

⇒ 5/2.

Hope it helps!